The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube Y and Cube Z. The tank is filled with some water. Cube Y is ²₃ filled with 39546 mℓ of water while Cube Z is completely filled with water. The height of the water level in Cube Y is 8 cm higher than that in Cube Z. Water is then drained from the tank and the height of the new water level is 6 cm. What is the volume of the water drained in mℓ?
²₃ of the volume of Cube Y = 39546 mℓ

Volume of Cube Y
= 39546 ÷ ²₃
= 39546 x ³₂
= 59319 mℓ

Length of Cube Y
= ³√59319
= 39 cm 

Height of water in Cube Y at first
= ²₃ x 39
= 26 cm

Height of Cube Z
= 26 - 8
= 18 cm

Height decrease in water in Cube Y after draining
= 26 - 6
= 20 cm

Height decrease in water in Cube Y after draining
= 18 - 6
= 12 cm

Volume of water drained in Cube Y
= 39 x 39 x 20
= 30420 mℓ

Volume of water drained in Cube Z
= 18 x 18 x 12
= 3888 mℓ

Total volume of water drained
= 30420 + 3888
= 34308 mℓ

Answer(s): 34308 mℓ