The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube R and Cube S. The tank is filled with some water. Cube R is ²₃ filled with 73728 mℓ of water while Cube S is completely filled with water. The height of the water level in Cube R is 8 cm higher than that in Cube S. Water is then drained from the tank and the height of the new water level is 6 cm. What is the volume of the water drained in mℓ?
²₃ of the volume of Cube R = 73728 mℓ

Volume of Cube R
= 73728 ÷ ²₃
= 73728 x ³₂
= 110592 mℓ

Length of Cube R
= ³√110592
= 48 cm 

Height of water in Cube R at first
= ²₃ x 48
= 32 cm

Height of Cube S
= 32 - 8
= 24 cm

Height decrease in water in Cube R after draining
= 32 - 6
= 26 cm

Height decrease in water in Cube R after draining
= 24 - 6
= 18 cm

Volume of water drained in Cube R
= 48 x 48 x 26
= 59904 mℓ

Volume of water drained in Cube S
= 24 x 24 x 18
= 10368 mℓ

Total volume of water drained
= 59904 + 10368
= 70272 mℓ

Answer(s): 70272 mℓ