The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube J and Cube K. The tank is filled with some water. Cube J is ²₃ filled with 6174 mℓ of water while Cube K is completely filled with water. The height of the water level in Cube J is 8 cm higher than that in Cube K. Water is then drained from the tank and the height of the new water level is 5 cm. What is the volume of the water drained in mℓ?
²₃ of the volume of Cube J = 6174 mℓ

Volume of Cube J
= 6174 ÷ ²₃
= 6174 x ³₂
= 9261 mℓ

Length of Cube J
= ³√9261
= 21 cm 

Height of water in Cube J at first
= ²₃ x 21
= 14 cm

Height of Cube K
= 14 - 8
= 6 cm

Height decrease in water in Cube J after draining
= 14 - 5
= 9 cm

Height decrease in water in Cube J after draining
= 6 - 5
= 1 cm

Volume of water drained in Cube J
= 21 x 21 x 9
= 3969 mℓ

Volume of water drained in Cube K
= 6 x 6 x 1
= 36 mℓ

Total volume of water drained
= 3969 + 36
= 4005 mℓ

Answer(s): 4005 mℓ