The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube Q and Cube R. The tank is filled with some water. Cube Q is ²₃ filled with 23958 mℓ of water while Cube R is completely filled with water. The height of the water level in Cube Q is 10 cm higher than that in Cube R. Water is then drained from the tank and the height of the new water level is 7 cm. What is the volume of the water drained in mℓ?
²₃ of the volume of Cube Q = 23958 mℓ

Volume of Cube Q
= 23958 ÷ ²₃
= 23958 x ³₂
= 35937 mℓ

Length of Cube Q
= ³√35937
= 33 cm 

Height of water in Cube Q at first
= ²₃ x 33
= 22 cm

Height of Cube R
= 22 - 10
= 12 cm

Height decrease in water in Cube Q after draining
= 22 - 7
= 15 cm

Height decrease in water in Cube Q after draining
= 12 - 7
= 5 cm

Volume of water drained in Cube Q
= 33 x 33 x 15
= 16335 mℓ

Volume of water drained in Cube R
= 12 x 12 x 5
= 720 mℓ

Total volume of water drained
= 16335 + 720
= 17055 mℓ

Answer(s): 17055 mℓ