The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube V and Cube W. The tank is filled with some water. Cube V is ⁴₅ filled with 72900 mℓ of water while Cube W is completely filled with water. The height of the water level in Cube V is 5 cm higher than that in Cube W. Water is then drained from the tank and the height of the new water level is 5 cm. What is the volume of the water drained in mℓ?
⁴₅ of the volume of Cube V = 72900 mℓ

Volume of Cube V
= 72900 ÷ ⁴₅
= 72900 x ⁵₄
= 91125 mℓ

Length of Cube V
= ³√91125
= 45 cm 

Height of water in Cube V at first
= ⁴₅ x 45
= 36 cm

Height of Cube W
= 36 - 5
= 31 cm

Height decrease in water in Cube V after draining
= 36 - 5
= 31 cm

Height decrease in water in Cube V after draining
= 31 - 5
= 26 cm

Volume of water drained in Cube V
= 45 x 45 x 31
= 62775 mℓ

Volume of water drained in Cube W
= 31 x 31 x 26
= 24986 mℓ

Total volume of water drained
= 62775 + 24986
= 87761 mℓ

Answer(s): 87761 mℓ