The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube N and Cube P. The tank is filled with some water. Cube N is ⁴₅ filled with 12500 mℓ of water while Cube P is completely filled with water. The height of the water level in Cube N is 10 cm higher than that in Cube P. Water is then drained from the tank and the height of the new water level is 8 cm. What is the volume of the water drained in mℓ?
⁴₅ of the volume of Cube N = 12500 mℓ

Volume of Cube N
= 12500 ÷ ⁴₅
= 12500 x ⁵₄
= 15625 mℓ

Length of Cube N
= ³√15625
= 25 cm 

Height of water in Cube N at first
= ⁴₅ x 25
= 20 cm

Height of Cube P
= 20 - 10
= 10 cm

Height decrease in water in Cube N after draining
= 20 - 8
= 12 cm

Height decrease in water in Cube N after draining
= 10 - 8
= 2 cm

Volume of water drained in Cube N
= 25 x 25 x 12
= 7500 mℓ

Volume of water drained in Cube P
= 10 x 10 x 2
= 200 mℓ

Total volume of water drained
= 7500 + 200
= 7700 mℓ

Answer(s): 7700 mℓ