A container holds some water up to a height of 104 cm. When 2 identical rubber balls are put into the container, the water level rises by 10 cm. One rubber ball is then removed from the tank, replaced by one metallic ball. The water level increases to 138 cm.
- Find the ratio of the volume of 1 rubber ball to 1 metallic ball.
- If the base area of the container is 108 cm², find the difference in the volume between the metallic ball and the rubber ball. Express your answer in cm³.
(a)
2 rubber balls → water level rises by 10 cm
Height of water per rubber ball
= 10 ÷ 2
= 5 cm
Height of water after one rubber ball is removed
= 104 + 10 - 5
= 109 cm
Height of water increased with 1 metallic ball
= 138 - 109
= 29 cm
Ratio of the change in height of the rubber ball to the metallic ball
= 5 : 29
(b)
Difference between the height of the metallic ball and the rubber ball
= 29 - 5
= 24 cm
Difference between volume of the metallic ball and the rubber ball
= 24 x 108
= 2592 cm
3 Answer(s): (a) 5 : 29; (b) 2592 cm
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