A container holds some water up to a height of 71 cm. When 9 identical rubber balls are put into the container, the water level rises by 27 cm. One rubber ball is then removed from the tank, replaced by one iron ball. The water level increases to 135 cm.

1. Find the ratio of the volume of 1 rubber ball to 1 iron ball.
2. If the base area of the container is 95 cm², find the difference in the volume between the iron ball and the rubber ball.  Express your answer in cm³.

(a)
9 rubber balls → water level rises by 27 cm

Height of water per rubber ball
= 27 ÷ 9
= 3 cm

Height of water after one rubber ball is removed
= 71 + 27 - 3
= 95 cm

Height of water increased with 1 iron ball
= 135 - 95
= 40 cm

Ratio of the change in height of the rubber ball to the iron ball
= 3 : 40 

(b)

Difference between the height of the iron ball and the rubber ball
= 40 - 3
= 37 cm

Difference between volume of the iron ball and the rubber ball
= 37 x 95
= 3515 cm³ 

Answer(s): (a) 3 : 40; (b) 3515 cm³