The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank K, measuring 58 m by 31 m by 25 m, is filled with water to its brim. Tank J is an empty cuboidal container with a length of 20 m. Slider 1 is lifted to release
15 of the water from Tank K to Tank J, after which the partition is slid down to separate Tank K and Tank J. Next, Slider 2 is removed and some water from Tank J flows into Tank H such that the height of the water level of Tank J and Tank H is 10 m.
- What is the length of Container H?
- How many m3 of water are there in Container J?
(a)
Volume of water in the Tank K that flows into the Container J
= 58 x 31 x 25 x
15 = 8990 m
3 Base area of Tank J and Tank H
= 8990 ÷ 10
= 899 m
2 Length of Tank H and Tank J
= 899 ÷ 31
= 29 m
Length of Tank H
= 29 - 20
= 9 m
(b)
Volume of water in Tank J
= 20 x 31 x 10
= 6200 m
3 Answer(s): (a) 9 m; (b) 6200 m
3