The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank G, measuring 44 m by 40 m by 30 m, is filled with water to its brim. Tank F is an empty cuboidal container with a length of 21 m. Slider 1 is lifted to release
35 of the water from Tank G to Tank F, after which the partition is slid down to separate Tank G and Tank F. Next, Slider 2 is removed and some water from Tank F flows into Tank E such that the height of the water level of Tank F and Tank E is 12 m.
- What is the length of Container E?
- How many m3 of water are there in Container F?
(a)
Volume of water in the Tank G that flows into the Container F
= 44 x 40 x 30 x
35 = 31680 m
3 Base area of Tank F and Tank E
= 31680 ÷ 12
= 2640 m
2 Length of Tank E and Tank F
= 2640 ÷ 40
= 66 m
Length of Tank E
= 66 - 21
= 45 m
(b)
Volume of water in Tank F
= 21 x 40 x 12
= 10080 m
3 Answer(s): (a) 45 m; (b) 10080 m
3