The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank V, measuring 54 m by 36 m by 20 m, is filled with water to its brim. Tank U is an empty cuboidal container with a length of 24 m. Slider 1 is lifted to release
13 of the water from Tank V to Tank U, after which the partition is slid down to separate Tank V and Tank U. Next, Slider 2 is removed and some water from Tank U flows into Tank T such that the height of the water level of Tank U and Tank T is 6 m.
- What is the length of Tank T?
- How many m3 of water are there in Tank U?
(a)
Volume of water in the Tank V that flows into the Tank U
= 54 x 36 x 20 x
13 = 12960 m
3 Base area of Tank U and Tank T
= 12960 ÷ 6
= 2160 m
2 Length of Tank T and Tank U
= 2160 ÷ 36
= 60 m
Length of Tank T
= 60 - 24
= 36 m
(b)
Volume of water in Tank U
= 24 x 36 x 6
= 5184 m
3 Answer(s): (a) 36 m; (b) 5184 m
3