The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank T, measuring 54 m by 30 m by 22 m, is filled with water to its brim. Tank S is an empty cuboidal container with a length of 22 m. Slider 1 is lifted to release ²₃ of the water from Tank T to Tank S, after which the partition is slid down to separate Tank T and Tank S. Next, Slider 2 is removed and some water from Tank S flows into Tank R such that the height of the water level of Tank S and Tank R is 8 m.

1. What is the length of Container R?
2. How many m³ of water are there in Container S?

(a)
Volume of water in the Tank T that flows into the Container S
= 54 x 30 x 22 x ²₃ 
= 23760 m³ 

Base area of Tank S and Tank R
= 23760 ÷ 8
= 2970 m² 

Length of Tank R and Tank S
= 2970 ÷ 30
= 99 m

Length of Tank R
= 99 - 22
= 77 m

(b)
Volume of water in Tank S
= 22 x 30 x 8
= 5280 m³ 

Answer(s): (a) 77 m; (b) 5280 m³