The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank U, measuring 54 m by 32 m by 25 m, is filled with water to its brim. Tank T is an empty cuboidal container with a length of 25 m. Slider 1 is lifted to release
23 of the water from Tank U to Tank T, after which the partition is slid down to separate Tank U and Tank T. Next, Slider 2 is removed and some water from Tank T flows into Tank S such that the height of the water level of Tank T and Tank S is 10 m.
- What is the length of Tank S?
- How many m3 of water are there in Tank T?
(a)
Volume of water in the Tank U that flows into the Tank T
= 54 x 32 x 25 x
23 = 28800 m
3 Base area of Tank T and Tank S
= 28800 ÷ 10
= 2880 m
2 Length of Tank S and Tank T
= 2880 ÷ 32
= 90 m
Length of Tank S
= 90 - 25
= 65 m
(b)
Volume of water in Tank T
= 25 x 32 x 10
= 8000 m
3 Answer(s): (a) 65 m; (b) 8000 m
3