The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank P, measuring 42 m by 36 m by 28 m, is filled with water to its brim. Tank N is an empty cuboidal container with a length of 24 m. Slider 1 is lifted to release
12 of the water from Tank P to Tank N, after which the partition is slid down to separate Tank P and Tank N. Next, Slider 2 is removed and some water from Tank N flows into Tank M such that the height of the water level of Tank N and Tank M is 14 m.
- What is the length of Container M?
- How many m3 of water are there in Container N?
(a)
Volume of water in the Tank P that flows into the Container N
= 42 x 36 x 28 x
12 = 21168 m
3 Base area of Tank N and Tank M
= 21168 ÷ 14
= 1512 m
2 Length of Tank M and Tank N
= 1512 ÷ 36
= 42 m
Length of Tank M
= 42 - 24
= 18 m
(b)
Volume of water in Tank N
= 24 x 36 x 14
= 12096 m
3 Answer(s): (a) 18 m; (b) 12096 m
3