The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank V, measuring 58 m by 36 m by 24 m, is filled with water to its brim. Tank U is an empty cuboidal container with a length of 26 m. Slider 1 is lifted to release
14 of the water from Tank V to Tank U, after which the partition is slid down to separate Tank V and Tank U. Next, Slider 2 is removed and some water from Tank U flows into Tank T such that the height of the water level of Tank U and Tank T is 6 m.
- What is the length of Tank T?
- How many m3 of water are there in Tank U?
(a)
Volume of water in the Tank V that flows into the Tank U
= 58 x 36 x 24 x
14 = 12528 m
3 Base area of Tank U and Tank T
= 12528 ÷ 6
= 2088 m
2 Length of Tank T and Tank U
= 2088 ÷ 36
= 58 m
Length of Tank T
= 58 - 26
= 32 m
(b)
Volume of water in Tank U
= 26 x 36 x 6
= 5616 m
3 Answer(s): (a) 32 m; (b) 5616 m
3