The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank P, measuring 52 m by 36 m by 30 m, is filled with water to its brim. Tank N is an empty cuboidal container with a length of 28 m. Slider 1 is lifted to release
34 of the water from Tank P to Tank N, after which the partition is slid down to separate Tank P and Tank N. Next, Slider 2 is removed and some water from Tank N flows into Tank M such that the height of the water level of Tank N and Tank M is 6 m.
- What is the length of Container M?
- How many m3 of water are there in Container N?
(a)
Volume of water in the Tank P that flows into the Container N
= 52 x 36 x 30 x
34 = 42120 m
3 Base area of Tank N and Tank M
= 42120 ÷ 6
= 7020 m
2 Length of Tank M and Tank N
= 7020 ÷ 36
= 195 m
Length of Tank M
= 195 - 28
= 167 m
(b)
Volume of water in Tank N
= 28 x 36 x 6
= 6048 m
3 Answer(s): (a) 167 m; (b) 6048 m
3