The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank T, measuring 60 m by 40 m by 21 m, is filled with water to its brim. Tank S is an empty cuboidal container with a length of 30 m. Slider 1 is lifted to release
23 of the water from Tank T to Tank S, after which the partition is slid down to separate Tank T and Tank S. Next, Slider 2 is removed and some water from Tank S flows into Tank R such that the height of the water level of Tank S and Tank R is 8 m.
- What is the length of Container R?
- How many m3 of water are there in Container S?
(a)
Volume of water in the Tank T that flows into the Container S
= 60 x 40 x 21 x
23 = 33600 m
3 Base area of Tank S and Tank R
= 33600 ÷ 8
= 4200 m
2 Length of Tank R and Tank S
= 4200 ÷ 40
= 105 m
Length of Tank R
= 105 - 30
= 75 m
(b)
Volume of water in Tank S
= 30 x 40 x 8
= 9600 m
3 Answer(s): (a) 75 m; (b) 9600 m
3