The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank P, measuring 60 m by 38 m by 20 m, is filled with water to its brim. Tank N is an empty cuboidal container with a length of 28 m. Slider 1 is lifted to release
12 of the water from Tank P to Tank N, after which the partition is slid down to separate Tank P and Tank N. Next, Slider 2 is removed and some water from Tank N flows into Tank M such that the height of the water level of Tank N and Tank M is 6 m.
- What is the length of Container M?
- How many m3 of water are there in Container N?
(a)
Volume of water in the Tank P that flows into the Container N
= 60 x 38 x 20 x
12 = 22800 m
3 Base area of Tank N and Tank M
= 22800 ÷ 6
= 3800 m
2 Length of Tank M and Tank N
= 3800 ÷ 38
= 100 m
Length of Tank M
= 100 - 28
= 72 m
(b)
Volume of water in Tank N
= 28 x 38 x 6
= 6384 m
3 Answer(s): (a) 72 m; (b) 6384 m
3