The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank G, measuring 54 m by 39 m by 20 m, is filled with water to its brim. Tank F is an empty cuboidal container with a length of 22 m. Slider 1 is lifted to release
35 of the water from Tank G to Tank F, after which the partition is slid down to separate Tank G and Tank F. Next, Slider 2 is removed and some water from Tank F flows into Tank E such that the height of the water level of Tank F and Tank E is 6 m.
- What is the length of Container E?
- How many m3 of water are there in Container F?
(a)
Volume of water in the Tank G that flows into the Container F
= 54 x 39 x 20 x
35 = 25272 m
3 Base area of Tank F and Tank E
= 25272 ÷ 6
= 4212 m
2 Length of Tank E and Tank F
= 4212 ÷ 39
= 108 m
Length of Tank E
= 108 - 22
= 86 m
(b)
Volume of water in Tank F
= 22 x 39 x 6
= 5148 m
3 Answer(s): (a) 86 m; (b) 5148 m
3