The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank U, measuring 54 m by 40 m by 28 m, is filled with water to its brim. Tank T is an empty cuboidal container with a length of 25 m. Slider 1 is lifted to release
12 of the water from Tank U to Tank T, after which the partition is slid down to separate Tank U and Tank T. Next, Slider 2 is removed and some water from Tank T flows into Tank S such that the height of the water level of Tank T and Tank S is 9 m.
- What is the length of Container S?
- How many m3 of water are there in Container T?
(a)
Volume of water in the Tank U that flows into the Container T
= 54 x 40 x 28 x
12 = 30240 m
3 Base area of Tank T and Tank S
= 30240 ÷ 9
= 3360 m
2 Length of Tank S and Tank T
= 3360 ÷ 40
= 84 m
Length of Tank S
= 84 - 25
= 59 m
(b)
Volume of water in Tank T
= 25 x 40 x 9
= 9000 m
3 Answer(s): (a) 59 m; (b) 9000 m
3