The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank G, measuring 42 m by 40 m by 25 m, is filled with water to its brim. Tank F is an empty cuboidal container with a length of 28 m. Slider 1 is lifted to release
23 of the water from Tank G to Tank F, after which the partition is slid down to separate Tank G and Tank F. Next, Slider 2 is removed and some water from Tank F flows into Tank E such that the height of the water level of Tank F and Tank E is 5 m.
- What is the length of Tank E?
- How many m3 of water are there in Tank F?
(a)
Volume of water in the Tank G that flows into the Tank F
= 42 x 40 x 25 x
23 = 28000 m
3 Base area of Tank F and Tank E
= 28000 ÷ 5
= 5600 m
2 Length of Tank E and Tank F
= 5600 ÷ 40
= 140 m
Length of Tank E
= 140 - 28
= 112 m
(b)
Volume of water in Tank F
= 28 x 40 x 5
= 5600 m
3 Answer(s): (a) 112 m; (b) 5600 m
3