The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank T, measuring 60 m by 39 m by 30 m, is filled with water to its brim. Tank S is an empty cuboidal container with a length of 29 m. Slider 1 is lifted to release
13 of the water from Tank T to Tank S, after which the partition is slid down to separate Tank T and Tank S. Next, Slider 2 is removed and some water from Tank S flows into Tank R such that the height of the water level of Tank S and Tank R is 15 m.
- What is the length of Container R?
- How many m3 of water are there in Container S?
(a)
Volume of water in the Tank T that flows into the Container S
= 60 x 39 x 30 x
13 = 23400 m
3 Base area of Tank S and Tank R
= 23400 ÷ 15
= 1560 m
2 Length of Tank R and Tank S
= 1560 ÷ 39
= 40 m
Length of Tank R
= 40 - 29
= 11 m
(b)
Volume of water in Tank S
= 29 x 39 x 15
= 16965 m
3 Answer(s): (a) 11 m; (b) 16965 m
3