The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank P, measuring 58 m by 34 m by 24 m, is filled with water to its brim. Tank N is an empty cuboidal container with a length of 20 m. Slider 1 is lifted to release
12 of the water from Tank P to Tank N, after which the partition is slid down to separate Tank P and Tank N. Next, Slider 2 is removed and some water from Tank N flows into Tank M such that the height of the water level of Tank N and Tank M is 6 m.
- What is the length of Container M?
- How many m3 of water are there in Container N?
(a)
Volume of water in the Tank P that flows into the Container N
= 58 x 34 x 24 x
12 = 23664 m
3 Base area of Tank N and Tank M
= 23664 ÷ 6
= 3944 m
2 Length of Tank M and Tank N
= 3944 ÷ 34
= 116 m
Length of Tank M
= 116 - 20
= 96 m
(b)
Volume of water in Tank N
= 20 x 34 x 6
= 4080 m
3 Answer(s): (a) 96 m; (b) 4080 m
3