The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank T, measuring 60 m by 31 m by 29 m, is filled with water to its brim. Tank S is an empty cuboidal container with a length of 20 m. Slider 1 is lifted to release
15 of the water from Tank T to Tank S, after which the partition is slid down to separate Tank T and Tank S. Next, Slider 2 is removed and some water from Tank S flows into Tank R such that the height of the water level of Tank S and Tank R is 6 m.
- What is the length of Tank R?
- How many m3 of water are there in Tank S?
(a)
Volume of water in the Tank T that flows into the Tank S
= 60 x 31 x 29 x
15 = 10788 m
3 Base area of Tank S and Tank R
= 10788 ÷ 6
= 1798 m
2 Length of Tank R and Tank S
= 1798 ÷ 31
= 58 m
Length of Tank R
= 58 - 20
= 38 m
(b)
Volume of water in Tank S
= 20 x 31 x 6
= 3720 m
3 Answer(s): (a) 38 m; (b) 3720 m
3