The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank Y, measuring 58 m by 38 m by 27 m, is filled with water to its brim. Tank X is an empty cuboidal container with a length of 20 m. Slider 1 is lifted to release
23 of the water from Tank Y to Tank X, after which the partition is slid down to separate Tank Y and Tank X. Next, Slider 2 is removed and some water from Tank X flows into Tank W such that the height of the water level of Tank X and Tank W is 6 m.
- What is the length of Container W?
- How many m3 of water are there in Container X?
(a)
Volume of water in the Tank Y that flows into the Container X
= 58 x 38 x 27 x
23 = 39672 m
3 Base area of Tank X and Tank W
= 39672 ÷ 6
= 6612 m
2 Length of Tank W and Tank X
= 6612 ÷ 38
= 174 m
Length of Tank W
= 174 - 20
= 154 m
(b)
Volume of water in Tank X
= 20 x 38 x 6
= 4560 m
3 Answer(s): (a) 154 m; (b) 4560 m
3