The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank T, measuring 45 m by 39 m by 27 m, is filled with water to its brim. Tank S is an empty cuboidal container with a length of 29 m. Slider 1 is lifted to release
25 of the water from Tank T to Tank S, after which the partition is slid down to separate Tank T and Tank S. Next, Slider 2 is removed and some water from Tank S flows into Tank R such that the height of the water level of Tank S and Tank R is 6 m.
- What is the length of Tank R?
- How many m3 of water are there in Tank S?
(a)
Volume of water in the Tank T that flows into the Tank S
= 45 x 39 x 27 x
25 = 18954 m
3 Base area of Tank S and Tank R
= 18954 ÷ 6
= 3159 m
2 Length of Tank R and Tank S
= 3159 ÷ 39
= 81 m
Length of Tank R
= 81 - 29
= 52 m
(b)
Volume of water in Tank S
= 29 x 39 x 6
= 6786 m
3 Answer(s): (a) 52 m; (b) 6786 m
3