The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank F, measuring 60 m by 38 m by 28 m, is filled with water to its brim. Tank E is an empty cuboidal container with a length of 22 m. Slider 1 is lifted to release
12 of the water from Tank F to Tank E, after which the partition is slid down to separate Tank F and Tank E. Next, Slider 2 is removed and some water from Tank E flows into Tank D such that the height of the water level of Tank E and Tank D is 12 m.
- What is the length of Container D?
- How many m3 of water are there in Container E?
(a)
Volume of water in the Tank F that flows into the Container E
= 60 x 38 x 28 x
12 = 31920 m
3 Base area of Tank E and Tank D
= 31920 ÷ 12
= 2660 m
2 Length of Tank D and Tank E
= 2660 ÷ 38
= 70 m
Length of Tank D
= 70 - 22
= 48 m
(b)
Volume of water in Tank E
= 22 x 38 x 12
= 10032 m
3 Answer(s): (a) 48 m; (b) 10032 m
3