The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank N, measuring 50 m by 40 m by 24 m, is filled with water to its brim. Tank M is an empty cuboidal container with a length of 29 m. Slider 1 is lifted to release ³₅ of the water from Tank N to Tank M, after which the partition is slid down to separate Tank N and Tank M. Next, Slider 2 is removed and some water from Tank M flows into Tank L such that the height of the water level of Tank M and Tank L is 8 m.

1. What is the length of Container L?
2. How many m³ of water are there in Container M?

(a)
Volume of water in the Tank N that flows into the Container M
= 50 x 40 x 24 x ³₅ 
= 28800 m³ 

Base area of Tank M and Tank L
= 28800 ÷ 8
= 3600 m² 

Length of Tank L and Tank M
= 3600 ÷ 40
= 90 m

Length of Tank L
= 90 - 29
= 61 m

(b)
Volume of water in Tank M
= 29 x 40 x 8
= 9280 m³ 

Answer(s): (a) 61 m; (b) 9280 m³