The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank H, measuring 60 m by 39 m by 20 m, is filled with water to its brim. Tank G is an empty cuboidal container with a length of 28 m. Slider 1 is lifted to release
25 of the water from Tank H to Tank G, after which the partition is slid down to separate Tank H and Tank G. Next, Slider 2 is removed and some water from Tank G flows into Tank F such that the height of the water level of Tank G and Tank F is 5 m.
- What is the length of Tank F?
- How many m3 of water are there in Tank G?
(a)
Volume of water in the Tank H that flows into the Tank G
= 60 x 39 x 20 x
25 = 18720 m
3 Base area of Tank G and Tank F
= 18720 ÷ 5
= 3744 m
2 Length of Tank F and Tank G
= 3744 ÷ 39
= 96 m
Length of Tank F
= 96 - 28
= 68 m
(b)
Volume of water in Tank G
= 28 x 39 x 5
= 5460 m
3 Answer(s): (a) 68 m; (b) 5460 m
3