The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank T, measuring 54 m by 30 m by 22 m, is filled with water to its brim. Tank S is an empty cuboidal container with a length of 29 m. Slider 1 is lifted to release
13 of the water from Tank T to Tank S, after which the partition is slid down to separate Tank T and Tank S. Next, Slider 2 is removed and some water from Tank S flows into Tank R such that the height of the water level of Tank S and Tank R is 9 m.
- What is the length of Container R?
- How many m3 of water are there in Container S?
(a)
Volume of water in the Tank T that flows into the Container S
= 54 x 30 x 22 x
13 = 11880 m
3 Base area of Tank S and Tank R
= 11880 ÷ 9
= 1320 m
2 Length of Tank R and Tank S
= 1320 ÷ 30
= 44 m
Length of Tank R
= 44 - 29
= 15 m
(b)
Volume of water in Tank S
= 29 x 30 x 9
= 7830 m
3 Answer(s): (a) 15 m; (b) 7830 m
3