The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank P, measuring 60 m by 33 m by 26 m, is filled with water to its brim. Tank N is an empty cuboidal container with a length of 25 m. Slider 1 is lifted to release
34 of the water from Tank P to Tank N, after which the partition is slid down to separate Tank P and Tank N. Next, Slider 2 is removed and some water from Tank N flows into Tank M such that the height of the water level of Tank N and Tank M is 5 m.
- What is the length of Container M?
- How many m3 of water are there in Container N?
(a)
Volume of water in the Tank P that flows into the Container N
= 60 x 33 x 26 x
34 = 38610 m
3 Base area of Tank N and Tank M
= 38610 ÷ 5
= 7722 m
2 Length of Tank M and Tank N
= 7722 ÷ 33
= 234 m
Length of Tank M
= 234 - 25
= 209 m
(b)
Volume of water in Tank N
= 25 x 33 x 5
= 4125 m
3 Answer(s): (a) 209 m; (b) 4125 m
3