The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank U, measuring 42 m by 35 m by 30 m, is filled with water to its brim. Tank T is an empty cuboidal container with a length of 26 m. Slider 1 is lifted to release
23 of the water from Tank U to Tank T, after which the partition is slid down to separate Tank U and Tank T. Next, Slider 2 is removed and some water from Tank T flows into Tank S such that the height of the water level of Tank T and Tank S is 8 m.
- What is the length of Tank S?
- How many m3 of water are there in Tank T?
(a)
Volume of water in the Tank U that flows into the Tank T
= 42 x 35 x 30 x
23 = 29400 m
3 Base area of Tank T and Tank S
= 29400 ÷ 8
= 3675 m
2 Length of Tank S and Tank T
= 3675 ÷ 35
= 105 m
Length of Tank S
= 105 - 26
= 79 m
(b)
Volume of water in Tank T
= 26 x 35 x 8
= 7280 m
3 Answer(s): (a) 79 m; (b) 7280 m
3