The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank F, measuring 50 m by 35 m by 27 m, is filled with water to its brim. Tank E is an empty cuboidal container with a length of 21 m. Slider 1 is lifted to release ³₅ of the water from Tank F to Tank E, after which the partition is slid down to separate Tank F and Tank E. Next, Slider 2 is removed and some water from Tank E flows into Tank D such that the height of the water level of Tank E and Tank D is 6 m.

1. What is the length of Container D?
2. How many m³ of water are there in Container E?

(a)
Volume of water in the Tank F that flows into the Container E
= 50 x 35 x 27 x ³₅ 
= 28350 m³ 

Base area of Tank E and Tank D
= 28350 ÷ 6
= 4725 m² 

Length of Tank D and Tank E
= 4725 ÷ 35
= 135 m

Length of Tank D
= 135 - 21
= 114 m

(b)
Volume of water in Tank E
= 21 x 35 x 6
= 4410 m³ 

Answer(s): (a) 114 m; (b) 4410 m³