The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank U, measuring 60 m by 36 m by 27 m, is filled with water to its brim. Tank T is an empty cuboidal container with a length of 27 m. Slider 1 is lifted to release ²₅ of the water from Tank U to Tank T, after which the partition is slid down to separate Tank U and Tank T. Next, Slider 2 is removed and some water from Tank T flows into Tank S such that the height of the water level of Tank T and Tank S is 8 m.

1. What is the length of Container S?
2. How many m³ of water are there in Container T?

(a)
Volume of water in the Tank U that flows into the Container T
= 60 x 36 x 27 x ²₅ 
= 23328 m³ 

Base area of Tank T and Tank S
= 23328 ÷ 8
= 2916 m² 

Length of Tank S and Tank T
= 2916 ÷ 36
= 81 m

Length of Tank S
= 81 - 27
= 54 m

(b)
Volume of water in Tank T
= 27 x 36 x 8
= 7776 m³ 

Answer(s): (a) 54 m; (b) 7776 m³