The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank U, measuring 60 m by 40 m by 24 m, is filled with water to its brim. Tank T is an empty cuboidal container with a length of 27 m. Slider 1 is lifted to release
25 of the water from Tank U to Tank T, after which the partition is slid down to separate Tank U and Tank T. Next, Slider 2 is removed and some water from Tank T flows into Tank S such that the height of the water level of Tank T and Tank S is 8 m.
- What is the length of Tank S?
- How many m3 of water are there in Tank T?
(a)
Volume of water in the Tank U that flows into the Tank T
= 60 x 40 x 24 x
25 = 23040 m
3 Base area of Tank T and Tank S
= 23040 ÷ 8
= 2880 m
2 Length of Tank S and Tank T
= 2880 ÷ 40
= 72 m
Length of Tank S
= 72 - 27
= 45 m
(b)
Volume of water in Tank T
= 27 x 40 x 8
= 8640 m
3 Answer(s): (a) 45 m; (b) 8640 m
3