The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank W, measuring 48 m by 32 m by 28 m, is filled with water to its brim. Tank V is an empty cuboidal container with a length of 21 m. Slider 1 is lifted to release
34 of the water from Tank W to Tank V, after which the partition is slid down to separate Tank W and Tank V. Next, Slider 2 is removed and some water from Tank V flows into Tank U such that the height of the water level of Tank V and Tank U is 6 m.
- What is the length of Container U?
- How many m3 of water are there in Container V?
(a)
Volume of water in the Tank W that flows into the Container V
= 48 x 32 x 28 x
34 = 32256 m
3 Base area of Tank V and Tank U
= 32256 ÷ 6
= 5376 m
2 Length of Tank U and Tank V
= 5376 ÷ 32
= 168 m
Length of Tank U
= 168 - 21
= 147 m
(b)
Volume of water in Tank V
= 21 x 32 x 6
= 4032 m
3 Answer(s): (a) 147 m; (b) 4032 m
3