The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank V, measuring 60 m by 34 m by 28 m, is filled with water to its brim. Tank U is an empty cuboidal container with a length of 28 m. Slider 1 is lifted to release
25 of the water from Tank V to Tank U, after which the partition is slid down to separate Tank V and Tank U. Next, Slider 2 is removed and some water from Tank U flows into Tank T such that the height of the water level of Tank U and Tank T is 6 m.
- What is the length of Container T?
- How many m3 of water are there in Container U?
(a)
Volume of water in the Tank V that flows into the Container U
= 60 x 34 x 28 x
25 = 22848 m
3 Base area of Tank U and Tank T
= 22848 ÷ 6
= 3808 m
2 Length of Tank T and Tank U
= 3808 ÷ 34
= 112 m
Length of Tank T
= 112 - 28
= 84 m
(b)
Volume of water in Tank U
= 28 x 34 x 6
= 5712 m
3 Answer(s): (a) 84 m; (b) 5712 m
3