The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank P, measuring 58 m by 38 m by 28 m, is filled with water to its brim. Tank N is an empty cuboidal container with a length of 30 m. Slider 1 is lifted to release
12 of the water from Tank P to Tank N, after which the partition is slid down to separate Tank P and Tank N. Next, Slider 2 is removed and some water from Tank N flows into Tank M such that the height of the water level of Tank N and Tank M is 14 m.
- What is the length of Tank M?
- How many m3 of water are there in Tank N?
(a)
Volume of water in the Tank P that flows into the Tank N
= 58 x 38 x 28 x
12 = 30856 m
3 Base area of Tank N and Tank M
= 30856 ÷ 14
= 2204 m
2 Length of Tank M and Tank N
= 2204 ÷ 38
= 58 m
Length of Tank M
= 58 - 30
= 28 m
(b)
Volume of water in Tank N
= 30 x 38 x 14
= 15960 m
3 Answer(s): (a) 28 m; (b) 15960 m
3