An empty rectangular tank has a capacity of 95 ℓ and a height of 19 cm. At 6 a.m., Tap S is turned on to fill the tank at a rate of 2 ℓ per minute for 20 minutes. After 2 minutes, Tap T is turned on to drain water from the tank at a rate of 2 ℓ per minute for 13 minutes. What is the height of the water level in the tank in the end? Give the answer in 1 decimal place.
1 ℓ = 1000 cm³ 
2 ℓ = 2000 cm³ 
2 ℓ = 2000 cm³ 
95 ℓ = 95000 cm³

Volume of water flowed in from Tap S
= 20 x 2000
= 40000 cm³

Volume of water from drained from Tap T
= 13 x 2000
= 26000 cm³

Volume of water left in the tank
= 40000 - 26000
= 14000 cm³

Base area of the tank
= 95000 ÷ 19
= 5000 cm² 

Height of water left in the tank
= 14000 ÷ 5000
≈ 2.8 cm

Answer(s): 2.8 cm