Figure S shows a closed rectangular tank of dimensions 44 cm by 44 cm by 85 cm with a cube of edge 23 cm glued to its bottom right corner. The tank contains 85 litres of water. Figure T shows the same rectangular tank lying on its side. Find the height of the water level, in centimetres, corrected to 2 decimal places.
Height of water under the cube in Figure T 
= 44 - 23
= 21 cm

Volume of water under the cube in Figure T 
= 85 x 44 x 21
= 78540 cm³ 

1 ℓ = 1000 
85 ℓ = 85000cm³ 

Volume of water beside the cube
= 85000 - 78540
= 6460 cm³ 

Base area of water beside the cube
= (44 x 85) - (23 x 23)
= 3740 - 529
= 3211 cm² 

Height of water level beside the cube
= 6460 ÷ 3211
≈ 2.01 cm

Height of the water level
= 2.01 + 23
≈ 25.01 cm

Answer(s): 25.01 cm