At first, Containers L, M and N contained water as shown. Some water from Containers M and N was poured into Container L without any spilling over. The volume of water left in Containers M and N is shown. What would be the volume of water in Container L?
1 ℓ = 1000 mℓ

Volume of water at each division on Container L
= 1000 ÷ 10
= 100 mℓ

Volume of water in Container L at first
= 6 x 100
= 600 mℓ

Volume of water at each division on Container M
= 900 ÷ 10
= 90 mℓ

Volume of water in Container M
= 8 x 90
= 720 mℓ

Volume of water at each division in Container N
= 800 ÷ 10
= 80 mℓ

Amount of water contained in Container N
= 9 x 80
= 720 mℓ

Total volume of water in Container M and Container N
= 720 + 720
= 1440 mℓ

Volume of water in Container M after pouring
= 6 x 90
= 540 mℓ

Volume of water in Container N after pouring
= 6 x 80
= 480 mℓ

Volume of water in Container M and Container N
= 540 + 480
= 1020 mℓ

Volume of water poured in Container L
= 1440 - 1020
= 420 mℓ

Total volume of water in Container L
= 600 + 420
= 1020 mℓ

Answer(s): 1020 mℓ