At first, Containers Y, Z and A contained water as shown. Some water from Containers Z and A was poured into Container Y without any spilling over. The volume of water left in Containers Z and A is shown. What would be the volume of water in Container Y?
2 ℓ = 2000 mℓ

Volume of water at each division on Container Y
= 2000 ÷ 10
= 200 mℓ

Volume of water in Container Y at first
= 6 x 200
= 1200 mℓ

Volume of water at each division on Container Z
= 700 ÷ 10
= 70 mℓ

Volume of water in Container Z
= 8 x 70
= 560 mℓ

Volume of water at each division in Container A
= 600 ÷ 10
= 60 mℓ

Amount of water contained in Container A
= 9 x 60
= 540 mℓ

Total volume of water in Container Z and Container A
= 560 + 540
= 1100 mℓ

Volume of water in Container Z after pouring
= 6 x 70
= 420 mℓ

Volume of water in Container A after pouring
= 6 x 60
= 360 mℓ

Volume of water in Container Z and Container A
= 420 + 360
= 780 mℓ

Volume of water poured in Container Y
= 1100 - 780
= 320 mℓ

Total volume of water in Container Y
= 1200 + 320
= 1520 mℓ

Answer(s): 1520 mℓ