At first, Containers T, U and V contained water as shown. Some water from Containers U and V was poured into Container T without any spilling over. The volume of water left in Containers U and V is shown. What would be the volume of water in Container T?
1 ℓ = 1000 mℓ

Volume of water at each division on Container T
= 1000 ÷ 10
= 100 mℓ

Volume of water in Container T at first
= 6 x 100
= 600 mℓ

Volume of water at each division on Container U
= 800 ÷ 10
= 80 mℓ

Volume of water in Container U
= 8 x 80
= 640 mℓ

Volume of water at each division in Container V
= 600 ÷ 10
= 60 mℓ

Amount of water contained in Container V
= 9 x 60
= 540 mℓ

Total volume of water in Container U and Container V
= 640 + 540
= 1180 mℓ

Volume of water in Container U after pouring
= 6 x 80
= 480 mℓ

Volume of water in Container V after pouring
= 6 x 60
= 360 mℓ

Volume of water in Container U and Container V
= 480 + 360
= 840 mℓ

Volume of water poured in Container T
= 1180 - 840
= 340 mℓ

Total volume of water in Container T
= 600 + 340
= 940 mℓ

Answer(s): 940 mℓ