At first, Containers W, X and Y contained water as shown. Some water from Containers X and Y was poured into Container W without any spilling over. The volume of water left in Containers X and Y is shown. What would be the volume of water in Container W?
1 ℓ = 1000 mℓ

Volume of water at each division on Container W
= 1000 ÷ 10
= 100 mℓ

Volume of water in Container W at first
= 6 x 100
= 600 mℓ

Volume of water at each division on Container X
= 900 ÷ 10
= 90 mℓ

Volume of water in Container X
= 8 x 90
= 720 mℓ

Volume of water at each division in Container Y
= 500 ÷ 10
= 50 mℓ

Amount of water contained in Container Y
= 9 x 50
= 450 mℓ

Total volume of water in Container X and Container Y
= 720 + 450
= 1170 mℓ

Volume of water in Container X after pouring
= 6 x 90
= 540 mℓ

Volume of water in Container Y after pouring
= 6 x 50
= 300 mℓ

Volume of water in Container X and Container Y
= 540 + 300
= 840 mℓ

Volume of water poured in Container W
= 1170 - 840
= 330 mℓ

Total volume of water in Container W
= 600 + 330
= 930 mℓ

Answer(s): 930 mℓ