At first, Containers X, Y and Z contained water as shown. Some water from Containers Y and Z was poured into Container X without any spilling over. The volume of water left in Containers Y and Z is shown. What would be the volume of water in Container X?
2 ℓ = 2000 mℓ

Volume of water at each division on Container X
= 2000 ÷ 10
= 200 mℓ

Volume of water in Container X at first
= 6 x 200
= 1200 mℓ

Volume of water at each division on Container Y
= 800 ÷ 10
= 80 mℓ

Volume of water in Container Y
= 8 x 80
= 640 mℓ

Volume of water at each division in Container Z
= 700 ÷ 10
= 70 mℓ

Amount of water contained in Container Z
= 9 x 70
= 630 mℓ

Total volume of water in Container Y and Container Z
= 640 + 630
= 1270 mℓ

Volume of water in Container Y after pouring
= 6 x 80
= 480 mℓ

Volume of water in Container Z after pouring
= 6 x 70
= 420 mℓ

Volume of water in Container Y and Container Z
= 480 + 420
= 900 mℓ

Volume of water poured in Container X
= 1270 - 900
= 370 mℓ

Total volume of water in Container X
= 1200 + 370
= 1570 mℓ

Answer(s): 1570 mℓ