At first, Containers R, S and T contained water as shown. Some water from Containers S and T was poured into Container R without any spilling over. The volume of water left in Containers S and T is shown. What would be the volume of water in Container R?
1 ℓ = 1000 mℓ

Volume of water at each division on Container R
= 1000 ÷ 10
= 100 mℓ

Volume of water in Container R at first
= 6 x 100
= 600 mℓ

Volume of water at each division on Container S
= 800 ÷ 10
= 80 mℓ

Volume of water in Container S
= 8 x 80
= 640 mℓ

Volume of water at each division in Container T
= 700 ÷ 10
= 70 mℓ

Amount of water contained in Container T
= 9 x 70
= 630 mℓ

Total volume of water in Container S and Container T
= 640 + 630
= 1270 mℓ

Volume of water in Container S after pouring
= 6 x 80
= 480 mℓ

Volume of water in Container T after pouring
= 6 x 70
= 420 mℓ

Volume of water in Container S and Container T
= 480 + 420
= 900 mℓ

Volume of water poured in Container R
= 1270 - 900
= 370 mℓ

Total volume of water in Container R
= 600 + 370
= 970 mℓ

Answer(s): 970 mℓ