At first, Containers J, K and L contained water as shown. Some water from Containers K and L was poured into Container J without any spilling over. The volume of water left in Containers K and L is shown. What would be the volume of water in Container J?
1 ℓ = 1000 mℓ

Volume of water at each division on Container J
= 1000 ÷ 10
= 100 mℓ

Volume of water in Container J at first
= 6 x 100
= 600 mℓ

Volume of water at each division on Container K
= 600 ÷ 10
= 60 mℓ

Volume of water in Container K
= 8 x 60
= 480 mℓ

Volume of water at each division in Container L
= 500 ÷ 10
= 50 mℓ

Amount of water contained in Container L
= 9 x 50
= 450 mℓ

Total volume of water in Container K and Container L
= 480 + 450
= 930 mℓ

Volume of water in Container K after pouring
= 6 x 60
= 360 mℓ

Volume of water in Container L after pouring
= 6 x 50
= 300 mℓ

Volume of water in Container K and Container L
= 360 + 300
= 660 mℓ

Volume of water poured in Container J
= 930 - 660
= 270 mℓ

Total volume of water in Container J
= 600 + 270
= 870 mℓ

Answer(s): 870 mℓ