At first, Containers Z, A and B contained water as shown. Some water from Containers A and B was poured into Container Z without any spilling over. The volume of water left in Containers A and B is shown. What would be the volume of water in Container Z?
2 ℓ = 2000 mℓ

Volume of water at each division on Container Z
= 2000 ÷ 10
= 200 mℓ

Volume of water in Container Z at first
= 6 x 200
= 1200 mℓ

Volume of water at each division on Container A
= 800 ÷ 10
= 80 mℓ

Volume of water in Container A
= 8 x 80
= 640 mℓ

Volume of water at each division in Container B
= 500 ÷ 10
= 50 mℓ

Amount of water contained in Container B
= 9 x 50
= 450 mℓ

Total volume of water in Container A and Container B
= 640 + 450
= 1090 mℓ

Volume of water in Container A after pouring
= 6 x 80
= 480 mℓ

Volume of water in Container B after pouring
= 6 x 50
= 300 mℓ

Volume of water in Container A and Container B
= 480 + 300
= 780 mℓ

Volume of water poured in Container Z
= 1090 - 780
= 310 mℓ

Total volume of water in Container Z
= 1200 + 310
= 1510 mℓ

Answer(s): 1510 mℓ