At first, Containers V, W and X contained water as shown. Some water from Containers W and X was poured into Container V without any spilling over. The volume of water left in Containers W and X is shown. What would be the volume of water in Container V?
1 ℓ = 1000 mℓ

Volume of water at each division on Container V
= 1000 ÷ 10
= 100 mℓ

Volume of water in Container V at first
= 6 x 100
= 600 mℓ

Volume of water at each division on Container W
= 700 ÷ 10
= 70 mℓ

Volume of water in Container W
= 8 x 70
= 560 mℓ

Volume of water at each division in Container X
= 600 ÷ 10
= 60 mℓ

Amount of water contained in Container X
= 9 x 60
= 540 mℓ

Total volume of water in Container W and Container X
= 560 + 540
= 1100 mℓ

Volume of water in Container W after pouring
= 6 x 70
= 420 mℓ

Volume of water in Container X after pouring
= 6 x 60
= 360 mℓ

Volume of water in Container W and Container X
= 420 + 360
= 780 mℓ

Volume of water poured in Container V
= 1100 - 780
= 320 mℓ

Total volume of water in Container V
= 600 + 320
= 920 mℓ

Answer(s): 920 mℓ