At first, Containers K, L and M contained water as shown. Some water from Containers L and M was poured into Container K without any spilling over. The volume of water left in Containers L and M is shown. What would be the volume of water in Container K?
2 ℓ = 2000 mℓ

Volume of water at each division on Container K
= 2000 ÷ 10
= 200 mℓ

Volume of water in Container K at first
= 6 x 200
= 1200 mℓ

Volume of water at each division on Container L
= 900 ÷ 10
= 90 mℓ

Volume of water in Container L
= 8 x 90
= 720 mℓ

Volume of water at each division in Container M
= 600 ÷ 10
= 60 mℓ

Amount of water contained in Container M
= 9 x 60
= 540 mℓ

Total volume of water in Container L and Container M
= 720 + 540
= 1260 mℓ

Volume of water in Container L after pouring
= 6 x 90
= 540 mℓ

Volume of water in Container M after pouring
= 6 x 60
= 360 mℓ

Volume of water in Container L and Container M
= 540 + 360
= 900 mℓ

Volume of water poured in Container K
= 1260 - 900
= 360 mℓ

Total volume of water in Container K
= 1200 + 360
= 1560 mℓ

Answer(s): 1560 mℓ